Number System Math Solved In Hindi

Important Math In Hindi (Number System Part-2)

 Helo Dosto Jaisey ke mey kaha tha ke Number System math Series ki Part-1  ka baad Part-2 mey bohot jald he aap sabhi ka pass layunga bo mey aaj ley aaya hu aaj ka part mey vi pichley ka tarah he 8-10 math hey aur isko mey saral sey saraltam rup mey samjhaney ka kosis kiya hu par agar phir vi aapko aaj ka math sab mey sey koi vi math samajh ney mey koi problem ho to uskey liye aap comment mujhsey bo puch saktey hey jo aap samajh nehi paa rahey hey. To chaliye bina samay gabaye Aaj ka IS Post Ko Suru Kartey Hey.

 To Dosto Aaj Mey Sabsey Pahley Number System Ka Ek Important Section Plus Ya Jog Section Sey puchey giye Sawal o ko hal karna Sikhayunga
Jog Section Sey Bohot Sarey Aap Vi Sayed Apna Apna Exam o mey jarur Dekhey Hongey Jaisey ke (i) Pratham $0 Tak Ke Sahi Prakit Sankhya O Ka Jog Kitna Hey Ya Phir 80 Tak Sama Sankhya O Ka Jog Kitna Hey istype Ka Question To Aap Sabhi Ney Exam O Mey Jarur Dekhey Honegey To Chaliye Sabsey Pahley Is Type Key Questin ko Hal Karna Sikhtey Hey  Jisko Mey Jog Section Ka Naam Diya Hu
Jog Section Ke Ganit Ko Agar hal Karna Hey To Sabsey Pahley Aap Sabhi Ko Sankhya O Ka Sreni Key Barey Pata Hona Jarury Hey Jissey Is Type KEy Question Ko Sahi Sey Hal Karney Mey Aap Sabhi Ko Kafi Subidha Mileygi To Chaliye List Key Jariye Important Sankhya Oo Ka Sreni Key Barey Mey Jantey Hey.

Purna Sankhya (Whole Number)	Sabhi Normal Number Jaisey- 0,1,2,3,4,5,6,7…
Prakit Sankhya (Nature Number)	Zero ko chorkey baki Key Number Jaisey- 1,2,3,4,5,6….
Bhajya Sankhya (Composite Number)	Jo Sankhya ko Bibhajit kiya ja sakta hey Jaisey 4,6,8,9,10…
Abhajya Sankhya (Prime Number)	Jo Sankhya Ko Bibhajit Nehi Kiya ja Sakta hey  jaisey – 2,3,5,7,11….
Sama Sankhya (Even Number)	Koi vi Sankhya jo Sankhya 2 Sey Purnata Bibhakt ho jata jaisey- 2,4,6,8,10….
Asama Sankhya (Odd Number)	Koi vi Sankhya jisey Sankhya 2 dwara Bibhakt nehi kiya ja sakta ho jaisey- 1,3,5,7,9,11….

Aab Jog Section Key Math Ko Solve Karney ka Kuch Mahatwapurna Sutra Sey Aap Sab Ko Abgat Karata Hu

 Sutra No. 1-  Agar Question Mey Pratham "n" Tak Ka Prakit Sankhya O Ka Jog Kitna Hey Is Type Ka Question Aayey To iskey Liye Sutra Hey =$\frac{n(n+1)}{2}$
  
Sutra No. 2- Agar Question Mey Pratham “n”  Sama Sankhya O Ka Jog Kitna Hey IS Type Ka Question Aaye To Uska Sutra  = n(n+1)

Sutra No. 3- Agar Question Mey   “n” tak Sama Sankhya O Ka Jog Kitna Hey IS type Ka Question Aaye To Uska Sutra  hey = $\frac{n}{2}(\frac{n}{2}+1)$

Sutra No. 4- Agar Question Mey “n” Tak Bisama Sankhya O Ka Jog Kitna Hey Is Type Ka Question Aaye To Us Ka Sutra Hey = n²

Aab Chaliye Har Sutra Sey Ek Ek Math Banakey Samjhaa tey hey

Sutra No. 1 Related Question – 40 Tak Ka Sabhi Prakit Sankhya O Ka Jog Fal Kitna Hey

To Isko Hal Karney Key Liye SabSey pahley Sutra Ko Prayog Kijiye Jatha =  $\frac{n(n+1)}{2}$Isko Prayog Kijiye Aaab Bas “n” Key Jagah Pey Question O Mey Diya Hua Man Ko Apply Karkey Katney Par Hey Aapko Aapkey Sawal Ka Answer Mil Jayega

Mera Rule- Par Par Par Agar Aapko Is Sustra Ko Yaad Rakhney Mey Dikkat Hota Ho To Aap Aur Ek Tarika Sey Vi Is Math Ko Solve Kar Saktey Ho But Mey To Aap Sabhi Ko Yehi Recommend Karunga ke Jo Original Niyom Heu Usisey Math Bananey Ka Kosis Kijiye But Agar Ek Dum Koi Upai Na Ho Taabhi Is Trick Ko Follow Kar Saktey Hey

To Iskey liye Aap Man Mey Sochiye Ke Koi Agar Aapsey Yeh Kahey Ke Pratham 40 Tak Sabhi Sankhya O Ka Jog Kitna Hey To Aap Bas 40 Adha Aadha karkey Bat Lijiye Matlab 40=20+20 .Aab 40 Sey Pahla   

20 Ko Guna Kijiye Aur Jo Gunfal Mileyga Uskey Sath Dusra 20 ko Jod Dijiye To Aapko Answer Mil Jayega

Sutra No.2 Sey related Question- Pratham 10 Sama Sankhya O Ka Jogfal Kitna Hey ?

Isko Vi Solve Karney Key Pichley Niyom Ke Jaisey He Iskey Sutra jatha = n(n+1) ko Prayog Kijiye Aur “n” Ke Jagah Pey Question Mey Diya Giya Man Ko Apply Karkey Katney Par he Aapko Answer Miil Jayega.

Mera Rule- Question Mey Jo Sankhya Diya Hu RaheyGa usey A Dharo Jaisey Yeha Sankhya 10= A Dharo Aab Is Sankhya Key Sath 1 Joro  matlab 10+1=11 aur is Sankhya ko B dharo aab ‘A” ko “B’’ sey Guna Karo Jaisey AxB Or 10x11 karney Par Aapko Answer mil Jayega.

Sutra No.3 Related Question- 68 Tak Ka Sama Sankhya O Ka Jogfal kitna Hey ?

Isko Vi Solve Karney Key Liye Pichley Tarah He Iska Sutra Ko Prayog

 Karo Jatha = $\frac{n}{2}(\frac{n}{2}+1)$  ko Prayog Karo Aur “n” Ke Jagah Pey Question Diya Giya Man Ko Use Karo Jaisey Is Question Mey Diya Giya Man Hey 68 matlab Yeha “n” = 68 hey

Mera Rule-  Isko Solve Karney Key Liye Question Mey Jo Man Diya Hua Rahey Pahley To Usey 2 Sey Divide Karey Fir jo Bhag Fal Mileyga Ga Usey A Dhariye jaisey IS Question Ka Man 68 ko Agar 2 Sey Bhag karengey to 68÷2 = 34 Bhagfal Mileyga Is 34 ko A Dhariye Aab Is Bhagfal Arthat 34 key Sath 1 joriye to aapko 34+1 = 35 yeh man mileyga Isey B Dhariye  Aab A ko B Key Sath guna (AxB)   karney Par apko Answer Mil Jayega

Sutra No.4 Related Question- 58 Tak Bisama Sankhya O Ka Jogfal Kitna Hey ?

IS Type ka Math Ko Solve Karna Sabsey Easy Hey Kiu Iska Sutra He Itna Easy Hey Just iska Sutra jatha = n² Ko Prayog Karey Aur ‘’n” Key Jagah Pey Question Mey Diya Hua Man Ko Apply Karey Jaisey Is Question Mey Diya Giya Man Hey 68 to Yeha “n”=68 hey.

Jog Section ko Yehi Pey Close Karkey Aab Mey Aap Sabhi Ikeai Ka Maan Nikalna Sikhata Hu

Question – (138)²¹³ Mey ikeai Ka Maan Kya Hey ?

Is Type Key Math Ko Solve karney Niyom Hey Hey Ke pahley Aap Base Number Ka Last Digit Ko Manyak Key Rup Mey Ley jaisey Is Question Mey Base Number Hey 138 Aur is ka last Digit Hey  Aab Is  8 ko (8)⁴ is Rup Mey To Aab ko jo Man Mileyga bo Is Prakar Ka Hoga (8)⁴ = 8x8x8x8 = 4096 Aab Is Sankhya ka last Digit matlab 6 ko hath mey Rakhiye.

Aab Second part mey Base Number Ka Last Digit Matlab 8 Ka Power ka man-- 4 Dekey, 138 ka power Ka man-- 213 ko, Bhag kijiye Matlab  213÷4 ,  isey bhag kijiye aur jo absist miley usey base number ka last digit key rupmey paribartit kijiye matlab agar absist 3 mila to 3 last digit lijiye aur usey aapas mey guna kijiye but agar 1 he absist miley to 1 he bar last digit ko use karey aab is maan key sath hath mey rakkha hua man ko guna kijiye aur jo parinam miley us sankhya ka last digit he question ka Answer hoga .

Isey Aur Achchey Sey SSamjahney Key liye Is Chitra Ko Dekhey

                                                                                                                       

Question- 867943 Mey 7 Key Sthaniya tatha jatiya man mey kya antar hey ?

Ans- sthaniya man ka matlab hota hey question mey jo sankhya diya hua hey usmey 7 ka position kaha hey hey jaisey hamarey is question mey sankhya 86 ka baad sankhya 7 hey aur jiskey baad aur tin sankhya hey 943 so joki 7 key baad tin sankhya hey to yeha pey 7 ka sthaniya man hoga 7 ka baad tin zero arthat  7 ka sthaniya maan hoga = 7000 agar 7 ka baad do sankhya hota to us abastha mey 7 ka sthaniya maan 700 hota

  7 ka jatiya maan 7 he hota hey ismey koi confusion nehi hey koi vi sankhya ka jatiya maan sayam bo sankhya he hoti hey jaisey 6 ka jatiya maan = 6 hoga . 9 ka jatiya maan 9 he hoga

To baad aab jab hamey sthaniya aur jatiya maan mil giya hey to aab simply dono maan ko ghatiye to aapko is question ka answer mil jayega

Jaisey (sthaniya man – jatiya man)

= (7000-7)

=6993

Question- Sankhya 1,2,3,4……………..98,99,100 ko paraspar guna jaye to gun fal key danye aur kitna sunya likhna hoga ?

Ans- Isko solve karney key liye hamesha ek baad yaad rakhiye ke do digit tak ke sankhya o ko aapas mey guna karney par do sanya parpta hota hey

Aur tin digit tak sankhya o ko aapas mey guna karney par tin sunya parpat hota hey .

To is hisab sey aagar prashna mey puchey giye sankhya o ko guna kiya jaye to jo parinam hamey mileyga bo nimna rup hoga

1 sey 10 tak sankhya o ko aapas mey guna karney par  Do zero miileyga

Isitarah 10 sey 20 tak , 20 sey 30 tak lagatar agagr 90 tak ke sankhya o ko aapas mey gina kiya jaye to har 10 key sankhya o pey do zero milengey yani 1 sey 90 tak mey total 2x9 = 18 zero milengey aur baki 90 sey 100 tak ke sankhya o ko aapas mey guna karney par joki 100 ek tin digit bala sankhya hey isiliye 90 sey 100 tak ke sankhya o ko aapas mey guna karney par tin zero milengey

To 1 sey 90 tak key sankhya o sey humey 18 zero mila

Aur 90 sey 100 tak key sankhya o sey humey 3 zero mila

Matlab 1 sey 100 tak ke sankhya o ko paraspar agar guna kiya jaye to

(18+3) yani 21 zero danye side mey likhna padeyga .

Question- 3 (tin) aank ki choti sey choti sankhya konsa hey jo 14 sey purnata bibhakt ho sakeyga ?

Ans- Is type ki math ko solve karney key liye sabsey pahley tin aank ke sabsey choti sankhya ko lijiye jo ke 100 hey aab 100 ko 14 sey bhag kijiye aur bhag karney par jo absisht miley ga uskey sath bo sankhya ko joriye jisey bhajak ka maan baney 

Jaisey  100 ko agar 14 sey bhag karengey to  aapko 2 absist mileyga bus aapko bo sankhya iskey satha jorna hey jissey bhajak ka maan baney matab 2 ka satha kitna jorney par bhajak arthat 14 ka baan baneyga bo sankhya apply karna padeyga tab apko is question ka answer mil jayega

Jaisey yeha pey jo ke 2 key sath 12 jorney par bhajak ka man mil raha hey isiliye answer hoga 100+12 = 112

Question- 5 aank ki bari sey bari sankhya konsa hey jisey 463 dwara purnata bibhak kiya ja sakeyga ?

Ans-  Is question ka solution rule bhi pahley jaisa he hey bus jo ke yeha pey bari bari sey bari sankhya ka barey mey pucha giya hey isiliye aapko bas 5 aank ki bari sey bari sankhya = 99999 ko 463 dwara bhag karna hey baki ka rule same he hey 

Question- Kon sa sankhya kisi prakrit sankhya ka barag nehi ho sakta

Ans- Is type key math aagar aapkey question mey aaye to  question mey jo option hongey  usmey jo option ka last digit mey 2,3,7,8 sankhya hongey bohi option is question ka answer hoga

Kiu ke koi vi sankhya ka last digit mey aagr 2,3,7 ya 8 hoga to bo koi bhi prakit sankhya ka barg nehi ho sakta hey.

Question– 6735*1 mey * key jagah pey konsa alpatama man rakhney sey sankhya 9 sey purnata bibhakt hoga ?

Ans- Is ko aaisey solve karey,

Sabsey pahley * key sthan par “” ko ley uskey baad prashna mey diya giya sankhya o ko joriye to issey is prakar ka parinam mileyga

Jatha = (6735*1)

           = (6+7+3+5+$x$+1)
           = (22+$x$+1))

Aab ko yeh dekhna hey 22 ka satha salpatama kon sa sankhya ko jorney par bo sankhya 9 sey purnata bibhakt ho payega

Jaisey aagar 22 ka sath 5 ko jorergey to aapko sankhya 27 mileyga jo ke 9 dwara purnata bibhakt ho jayega

Isiliye hum kah saktey hey ke * ki jagah pey sankhya 5 ko rakhney par mul sankhya 9 dwara sampurna bibhakt ho jayega .

Question– Kisi do ankiya sankhya ko do bar sath sath likhkar ek char ankiya sankhya banaiye jati hey jaisey 1313, 2727 ko kon sankhya dwara purnata bibhakt kiya ja sakeyga ?

Ans- IS type ki math ko solve karney ka sabsey aachcha aur easy tarika yehi hey ke bus aap yeh yaad rakhiye ke agar paraspar do sankhya  jaisey 1313 is type ka sankhya ho to bo 101 dwara bibhakt  hota hey aur agar paraspar tin sankhya jaisey 131131 is type ka sankhya ho to bo 1001 dwara bobhakt hota hey aisey he agar paraspar char sankhya ho to 10001 dwara bibhakt hota hey.

Dosto Aur ek Last Part Ayega Number System Ka Uska Baad Number System Series Pura Ho jayega aapko yeh Series Sey Koi math agar Samajh na aaye to uskey liye comment karey mey wada karta hu aap sabki prashna ka uttar mey jarur dunga taki koi is series ka koi bhi math ko samajh ney mey aap sabi ko kisivi prakar ka problem na ho 


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Aagar Aap Number System Part-1  Nehi Pad Paye Ho To Yeha --- Click Kijiye