Number System Math Solved

Math Solved In Hindi (Number System)

Niyom कि इस सृंखला में आप सभी का स्वागत हे आज हम संख्या पद्धति या Number System math को सोल्व करना सीखेंगे इस चैप्टर को मे दो या तिन पार्ट मे करूँगा ताकि इस सीरीज से कोईभि question छूट ना पाय। तो चलिए सुरु करते हे आज के  इस  पोस्ट को।

                        Number System Math In Hindi (Part-1)

Question - 5000+4000-1000+500-500 = ?

Ans- Isko solve karney ka sabsey asan tarika hey, pahley Plus baley mano ko joriye then minus baley mano ko joriye then plus baley mano sey minus baley mano ko ghatiiye tab apko sahi answer mil jayega

To isko follow karkey aab hum hamarey prashna ka answer nikaltey hey

+5000+4000+500-1000-500

=+9500-1500

=8000

Question- 1522 X 99= ?

Ans- Is type key math jismey dusra man 99 ya 999 ya 9999 mey hota hey usko dusra rupmey likhey taki apko guna karney mey subidha miley jaisey agar aap ko sankhya ko 9999 sey guna karengey to aapko bohot jada time lageyga par agar bohi sankhya ko aap 99= (10000-1) sey guna karengey to bo bohot e jaldi ho jayega

To isko follow karkey aab hum hamarey prashna ka answer nikaltey hey

1522 X 99

1522 X (100-1)

= 152200-1522

=150678

Question- 16X12-672÷21 = ?-211

Ans- Isko solve karney key liye sabsey pahley math ko do side mey bat lijiye

Jaisey 16X12-672÷21 = A maniye Aur “?”-211 ko B maniye

Aab “A”  Part Ko Solve Kar Lijiye

Jo Is Prakar hoga

16X12-672÷21 = 192-32

                            =160

Aab Aapko Yeh Dekhna Hey Ke Kon Sankhya Sey 211 ko ghataney sey 160 Hoga

Aur iskey Liye Apko 211 ke sath 160 ko jorna padega tab aapko answer mil jayega yani              

211+160 = 371 Yani Prashna Mey Pucha Giya Sankhya Hoga 371

Question- $\left( 1-\frac{1}{3} \right)\left( 1-\frac{1}{4} \right)\left( 1-\frac{1}{5} \right)\ldots ..\left( 1-\frac{1}{n} \right)$ =?

Ans- Is Type Ke Math Ko Bohot Tarika ka sey kiya ja sakta hey par mey specialy jis tarika sey karta  bohi aapko bata raha hu

Ha to dosto is type ke math ko bananey key liye aap ko ek baat yaad rakhna hey ke prashna mey jo bich mey dot dot dot diya hua hey uska

Matlab hey ke yeha Har ka maan Single Digit sey Double digit tak jar aha hey

Matlab yeha man $1-\frac{1}{3}sey1-\frac{1}{10}$tak ja raha hey

Yani yeha “n” ka matlab 10 hey

Aab simply aap lagatar sabka manko nikaley  jo jada muskil nehi  ismey aapko karna yehi hey k eek ka man nikal ley fir jo man nikalta hey uskey ansh mey aur har mey 1 jortey rahiye issey asani sey aap sabka man nikal saktey hey

Jaisey  $1-\frac{1}{3}=\frac{3-1}{3}=\frac{2}{3}$hoga  

Isi tarah Bad key man Hoga $(1-\frac{1}{4})=\frac{2+1}{3+1}=\frac{3}{4},\frac{4}{5},\frac{5}{6},\frac{6}{7},\frac{7}{8},\frac{8}{9},\frac{9}{10}$

Aab jo ke hum har key double digit mean 10 tak pohoch giye hey isiliye aab humey sabka man mil chukka hey

        Aab isey katna parega  $\frac{2}{3}X\frac{3}{4}X\frac{4}{5}X\frac{5}{6}X\frac{6}{7}X\frac{7}{8}X\frac{8}{9}X\frac{9}{10}$

      Katney ka baad jo man nikleyga bo hoga    = $\frac{2}{10}$aab aap “n” ka jo man sochey they usko yeha lagana padega

Jaisey yeha pey  “n” ka maan  Humlog 10 sochey they to yeha joki n=10 hey isiliye sankhya 10 key jagah par hum  n akshar ko likhengey

Matlab is prashna ka answer hoga $\frac{2}{10}=\frac{2}{n}$

Question- (999)²-(998)²

Ans- Iska man nikalney key liye aapko ek sutra yaad rakhna hey aur usey prayog bhii karna hey

Sutra hey (a)²-(b)² = (a+b)X(a-b)

To isko apply karney sey jo man niklega bo is prakar hoga

(999)²-(998)² = (999+998)X(999-998)

                        =1997 X 1

                        = 1997

Questiion- $(1\frac{1}{2}+11\frac{1}{2}+111\frac{1}{2}+1111\frac{1}{2})$ = ?

Ans- Is type ke math ko solve karney key liye sabsey pahley inkey manko nikal lijiye

Jo is prakar hoga $(1\frac{1}{2}+11\frac{1}{2}+111\frac{1}{2}+1111\frac{1}{2})$

                             = $\frac{3}{2}+\frac{23}{2}+\frac{223}{2}+\frac{2223}{2}$

Aab $\frac{1}{2}$  ko common ley lijiye = $\frac{1}{2}(3+23+223+2223)$

                                                  =$\frac{1}{2}X2472$

                                                    = 1236

Isi tarah aab isko katney par aapko answer mil jayega jeisa is question ka answer hoga 1236

Question- Agar 4^a=5, 5^b=6, 6^c=7, 7^d=8 hey to axbxcxd = ?

Ans- Is type ke math ko solve karney key liye sabsey pahley aap last sankhya ko lekey man nikaliye

Jaisey yeha pey hum sabsey pahley 7^d = 8 ko lengey

Aab dekhiye 7^d = 8 ko hum 8 = 7^d bhi likh saktey ho

To aab hum agar har man ko sahi sahi baithayengey to humey iska answer mil jayega

Jaisey 8 = 7^d

      Aab jo ke 6^c = 7 hey ya 7 = 6^c hey isiliye hum 7 ke jagah pey 6^c ko baithayengey

To aab jo man mileyga bo is tarh hoga

8=7^d

= 8 = 6^cd

Isi tarah baki key man ko nikalney par humey jo man mileyga bo is prakar hoga

8 = 6^cd

Then 8 = 5^bcd

Then 8 = 4^abcd

Yani 4^abcd = 8

Then abcd = $\frac{8}{4}$

So abcd = 2

Question- $\frac{693X693X693-383X383X383}{693X693+693X383+383X383}$   =?

Ans- isko solve karney key liye hum eek sutra yaad rakhna padega aur jisko proyog karkey he humey is sawal key jabab mil saktey hey

Bo formula hey a³-b³ = (a-b)(a²+ab+b²)

To aab agar is formula ko is question mey apply kiya jaye to jo parinam hoga

Yeha pey 693=a, 383=b mankey chaliye

To $\frac{693X693X693-383X383X383}{693X693+693X383+383X383}$

=  $\frac{axaxa-bxbxb}{axa+axb+bxb}$  

= $\frac{{{\text{a}}^{3}}-{{\text{b}}^{3}}}{{{\text{a}}^{2}}+\text{ab}+{{\text{b}}^{2}}}$

^{= $\frac{\left( a-b \right)\left( {{\text{a}}^{2}}+\text{ab}+{{\text{b}}^{2}} \right)}{\left( {{a}^{2}}+ab+{{b}^{2}} \right)}$}

Aab yeha pey agar a and b ka man ko put karengey to payengey

Yeh man = $\frac{\left( 693-383 \right)({{693}^{2}}+693x383+{{383}^{2}}}{\left( {{693}^{2}}+693+383+{{383}^{2}} \right)}$

Aab isko katney par humey answer mil jayega

Joke hoga (693-383) = 310

Question- 10690 ko kisi sankhya sey bhag deney par bhagfal =73 tatha seshfal = 32 prapt hota hey

To bhajak kitna hoga =?

Ans- is math ko solve karney purb apko yeh janna abasyak hey ke

Bhajya, bhajak, bhagfal aur seshfal kon kon hey

Isey chitra mey samjhiye

Aab apko karna ke vajya sey seshfal ko ghatana padega aur jo man prapt hota hey usey bhagfal dwara bhag karna padega

Yani $\frac{\left( Vajya-Seshfal \right)}{Bhagfal}$ = $\frac{\left( 10690-32 \right)}{73}$

                                 = $\frac{10658}{73}$

                                  =146 yehi answer hey is Question ka

Question- 4508 ke samiptama kon se sankhya hey jo 21 sey purnata bibhakt ho ?

Ans- Is type ke math ko solve kartey samay aapko yeh dhyan mey rakhna hey neya man jaisey 4508 sey adhik ho

Aur isko dhyanmey rakhtey huye aab apko 4508 ko 21 sey bhag karna padega

Bhag karney par aapko mileyga

4508÷21= Bhagfal hoga 214 aur Seshfal mileyga 14

Iska matlab seshfal agar aur 7 jora jaiye to bo 21 dwara bibhakt hoga

Matlab agar seshfal 14 key sath aur sankhya 7 ko milaya jaye to man baneyga 21

Aur tab neya sankhya jorney par bhajya ka man hoga 4508+7 = 4515 jo  21 sey purnata

Bibhakt ho jayega

To  yeha pey answer hoga = 4515

Number System Part-2 padney Key Liye yeha Click Kijiye

दोस्तों आज का मेरा यह पोस्ट आप सभी को कैसा लगा यह कमेंट में जरूर बताइयेगा आप सभी के कमेंट का इन्तेजार में रहूँगा और दोस्तों अगला पार्ट मे बोहोत जल्द हि  लायुंगा तब तक इस पार्ट को अच्छा से समझिये और अगर  कही पर भि समझ ने में दिक्कत होता हो  तो कमेंट में मुझे बताइये वादा  करता हु मे उसका जबाब जरूर दूंगा ताकि आपको इस चैप्टर को समझने में कोई प्रॉब्लम न हो।  तो दोस्तों अभी के लिए बाई मिलते हे Next पोस्टमे। 

 Bye . 

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